(7x-4)(x^2-3x-1)=

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Solution for (7x-4)(x^2-3x-1)= equation: 


Simplifying
(7x + -4)(x2 + -3x + -1) = 0

Reorder the terms:
(-4 + 7x)(x2 + -3x + -1) = 0

Reorder the terms:
(-4 + 7x)(-1 + -3x + x2) = 0

Multiply (-4 + 7x) * (-1 + -3x + x2)
(-4(-1 + -3x + x2) + 7x * (-1 + -3x + x2)) = 0
((-1 * -4 + -3x * -4 + x2 * -4) + 7x * (-1 + -3x + x2)) = 0
((4 + 12x + -4x2) + 7x * (-1 + -3x + x2)) = 0
(4 + 12x + -4x2 + (-1 * 7x + -3x * 7x + x2 * 7x)) = 0
(4 + 12x + -4x2 + (-7x + -21x2 + 7x3)) = 0

Reorder the terms:
(4 + 12x + -7x + -4x2 + -21x2 + 7x3) = 0

Combine like terms: 12x + -7x = 5x
(4 + 5x + -4x2 + -21x2 + 7x3) = 0

Combine like terms: -4x2 + -21x2 = -25x2
(4 + 5x + -25x2 + 7x3) = 0

Solving
4 + 5x + -25x2 + 7x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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